An Oil Pump Is Drawing 44kw Of Electric Power
Hydraulic Pump Power
The ideal hydraulic power to drive a pump depends on
- the mass flow rate the
- liquid density
- the differential height
- either it is the static lift from one height to an other or the total head loss component of the system - and can be calculated like
P h(kW) = q ρ g h / (3.6 106)
=q p / (3.6 106) (1)
where
P h(kW) = hydraulic power (kW)
q = flow (m3/h)
ρ = density of fluid (kg/m3)
g = acceleration of gravity (9.81 m/s2)
h = differential head (m)
p = differeential pressure (N/m2, Pa)
The hydraulic Horse Power can be calculated as:
P h(hp) =P h(kW) / 0.746 (2)
where
P h(hp) = hydraulic horsepower (hp)
Or - alternatively
P h(hp) = qgpm hft SG / (3960 η) (2b)
where
qgpm = flow (gpm)
hft = differential head (ft)
SG = Specific Gravity (1 for water)
η = pump efficiency
Example - Power pumping Water
1 m3/h of water is pumped a head of 10 m. The theoretical pump power can be calculated as
Ph(kW) = (1 m3/h) (1000 kg/m3) (9.81 m/s2) (10 m) / (3.6 106)
= 0.027 kW
Shaft Pump Power
The shaft power - the power required transferred from the motor to the shaft of the pump - depends on the efficiency of the pump and can be calculated as
P s(kW) = P h(kW) / η (3)
where
P s(kW) = shaft power (kW)
η = pump efficiency
Online Pump Calculator - SI-units
The calculator below can used to calculate the hydraulic and shaft power of a pump:
Online Pump Calculator - Imperial units
The calculator below can used to calculate the hydraulic and shaft power of a pump using Imperial units:
- Check the relation between Density, Specific Weight and Specific Gravity
- Make Shortcut to this Calculator on Your Home Screen?
Related Mobile Apps from The Engineering ToolBox
- Pump Calculator App
- free apps for offline use on mobile devices.
An Oil Pump Is Drawing 44kw Of Electric Power
Source: https://www.engineeringtoolbox.com/pumps-power-d_505.html
Posted by: matterathationdeas02.blogspot.com
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